Question
Here is triangle ABC with AB = 5 cm, BC = 10 cm, and AC = 5√7 cm. Find the size of angle ABC. You must show all your working.
Worked Solution
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Use the cosine rule to find angle B. The cosine rule states: AC² = AB² + BC² – 2 · AB · BC · cos B.
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Substitute the known values: (5√7)² = 5² + 10² – 2(5)(10) cos B. Calculate each term: (5√7)² = 175, 5² = 25, 10² = 100. So 175 = 125 – 100 cos B.
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Rearrange: 100 cos B = 125 – 175 = –50, so cos B = –50/100 = –1/2.
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Find the angle: B = cos⁻¹(–1/2) = 120°.
120°
Forgetting to rearrange the cosine rule correctly: cos B = (AB² + BC² – AC²) / (2 · AB · BC). Getting the numerator wrong (adding AC² instead of subtracting) gives the wrong sign for cos B.
Assessment Objectives (question level, Edexcel 1MA1 spec — not per step)